What is the integral from 0 to pi/2 of-cos(x)+1 ?

The integral from 0 to pi/2 of-cos(x)+1 is -1+pi/2

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integral from 0 to pi/2 of-cos(x)+1

\int_{0}^{\frac{π}{2}} - cos (x) + 1 d x

- 1 + \frac{π}{2}

Decimal

0.57079 \dots

Solution steps

\int_{0}^{\frac{π}{2}} - cos (x) + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{\frac{π}{2}} cos (x) d x + \int_{0}^{\frac{π}{2}} 1 d x

\int_{0}^{\frac{π}{2}} cos (x) d x = 1

\int_{0}^{\frac{π}{2}} 1 d x = \frac{π}{2}

= - 1 + \frac{π}{2}

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What is the integral from 0 to pi/2 of-cos(x)+1 ?
The integral from 0 to pi/2 of-cos(x)+1 is -1+pi/2