What is the derivative of (4x^2-16/(x-2)) ?

The derivative of (4x^2-16/(x-2)) is 4

What is the first derivative of (4x^2-16/(x-2)) ?

The first derivative of (4x^2-16/(x-2)) is 4

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\frac{d}{d x} (\frac{4 x ^{2} - 16}{x - 2})

4

Solution steps

\frac{d}{d x} (\frac{4 x ^{2} - 16}{x - 2})

Simplify

\frac{4 x ^{2} - 16}{x - 2} : 4 (x + 2)

= \frac{d}{d x} (4 (x + 2))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 4 (\frac{d x}{d x} + \frac{d}{d x} (2))

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 4 (1 + 0)

Simplify

= 4

\int x^{2} - x y d y

f (x) = \frac{1}{x}, (1, 1)

arccos (e^{9 x})

e^{- x + 1} \cdot x - 2 \cdot e^{- x + 1}

\frac{d}{d x} (0.5 sin (2 x))

What is the derivative of (4x^2-16/(x-2)) ?
The derivative of (4x^2-16/(x-2)) is 4
What is the first derivative of (4x^2-16/(x-2)) ?
The first derivative of (4x^2-16/(x-2)) is 4