What is (\partial)/(\partial x)(-cos(x)) ?

The answer to (\partial)/(\partial x)(-cos(x)) is sin(x)

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(\partial)/(\partial x)(-cos(x))

\frac{\partial}{\partial x} (- cos (x))

sin (x)

Solution steps

\frac{\partial}{\partial x} (- cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= - (- sin (x))

Simplify

= sin (x)

\int \frac{x ^{2} + 3 x + 7}{x} d x

y = 5 x^{2} e^{2 x}

y = 4 \cdot 5^{x}

\frac{d}{d x} (\frac{x ( x ^{2} - 1 )}{x ^{2} + 1})

What is (\partial)/(\partial x)(-cos(x)) ?
The answer to (\partial)/(\partial x)(-cos(x)) is sin(x)