What is area y=2sqrt(x),y=(x^2)/4 ?

The answer to area y=2sqrt(x),y=(x^2)/4 is 16/3

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area y=2sqrt(x),y=(x^2)/4

area

y = 2 x, y = \frac{x ^{2}}{4}

\frac{16}{3}

Decimal Notation

5.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} 2 x - \frac{x ^{2}}{4} d x

Solve

\int_{0}^{4} 2 x - \frac{x ^{2}}{4} d x : \frac{16}{3}

The area is:

= \frac{16}{3}

\frac{d}{d x} (ln (x^{2} - 2))

\int \frac{1}{( x + 5 ) ^{2} ( x - 2 )} d x

\frac{\partial}{\partial y} (\frac{5 x y}{x - y})

f (x) = x + \frac{3}{x}

(2 x - 1) e^{x}

What is area y=2sqrt(x),y=(x^2)/4 ?
The answer to area y=2sqrt(x),y=(x^2)/4 is 16/3