What is the integral from 0 to 1 of (3x^2+2x+1) ?

The integral from 0 to 1 of (3x^2+2x+1) is 3

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integral from 0 to 1 of (3x^2+2x+1)

\int_{0}^{1} (3 x^{2} + 2 x + 1) d x

3

Solution steps

\int_{0}^{1} 3 x^{2} + 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 3 x^{2} d x + \int_{0}^{1} 2 x d x + \int_{0}^{1} 1 d x

\int_{0}^{1} 3 x^{2} d x = 1

\int_{0}^{1} 2 x d x = 1

\int_{0}^{1} 1 d x = 1

= 1 + 1 + 1

Simplify

= 3

\frac{d}{d x} (\frac{2}{1 - x})

\int_{- \infty}^{0} \frac{1}{3 - 8 x} d x

\frac{\partial}{\partial x} (tan (x + y))

\int ln (r^{2}) d r

y^{^{'}} = 5 y sin (4 x)

What is the integral from 0 to 1 of (3x^2+2x+1) ?
The integral from 0 to 1 of (3x^2+2x+1) is 3