What is the derivative of-243sin(3x) ?

The derivative of-243sin(3x) is -729cos(3x)

What is the first derivative of-243sin(3x) ?

The first derivative of-243sin(3x) is -729cos(3x)

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\frac{d}{d x} (- 243 sin (3 x))

- 729 cos (3 x)

Solution steps

\frac{d}{d x} (- 243 sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 243 \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - 243 cos (3 x) \cdot 3

Simplify

= - 729 cos (3 x)

ln (e^{3 x})

(t^{2} - 3)^{2}

\frac{d}{d x} (\frac{x + 3}{x - 2})

\frac{\partial}{\partial x} (x y^{3} + 2 x y)

x \to \infty lim (tan (\frac{2 x π}{1 + 8 x}))

What is the derivative of-243sin(3x) ?
The derivative of-243sin(3x) is -729cos(3x)
What is the first derivative of-243sin(3x) ?
The first derivative of-243sin(3x) is -729cos(3x)