What is (\partial)/(\partial x)(-3sin(4x)) ?

The answer to (\partial)/(\partial x)(-3sin(4x)) is -12cos(4x)

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(\partial)/(\partial x)(-3sin(4x))

\frac{\partial}{\partial x} (- 3 sin (4 x))

- 12 cos (4 x)

Solution steps

\frac{\partial}{\partial x} (- 3 sin (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{\partial}{\partial x} (sin (4 x))

Apply the chain rule:

cos (4 x) \frac{\partial}{\partial x} (4 x)

= cos (4 x) \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (4 x) = 4

= - 3 cos (4 x) \cdot 4

Simplify

= - 12 cos (4 x)

t - 4

f (x) = \frac{7}{x , at ( 4 , \frac{7}{2} )}

f (x) = - x^{3}

x^{2} \frac{d y}{d x} + (x^{2} + 2 x) y = e^{x}

x^{2} y^{^{'}} + y^{2} = x y

What is (\partial)/(\partial x)(-3sin(4x)) ?
The answer to (\partial)/(\partial x)(-3sin(4x)) is -12cos(4x)