What is the limit as x approaches 0+of x^{-1/2} ?

The limit as x approaches 0+of x^{-1/2} is infinity

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limit as x approaches 0+of x^{-1/2}

x \to 0 + lim (x^{- \frac{1}{2}})

\infty

Solution steps

x \to 0 + lim (x^{- \frac{1}{2}})

Apply exponent rules

= x \to 0 + lim (e^{- \frac{1}{2} l n (x)})

Apply the Limit Chain Rule:

\infty

= \infty

x \to 3 lim (x^{2} - 8 x + 16)

x \to 0 lim (\frac{sin ( 8 x ) - 2}{x})

x \to 0 lim (ln (3 x))

x \to 0 lim (f (x) (1 - x^{2}))

x \to 9 lim (x + 3)

What is the limit as x approaches 0+of x^{-1/2} ?
The limit as x approaches 0+of x^{-1/2} is infinity