What is the integral of (xsqrt(x+5)) ?

The integral of (xsqrt(x+5)) is 2/5 (x+5)^{5/2}-10/3 (x+5)^{3/2}+C

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integral of (xsqrt(x+5))

\int (x x + 5) d x

\frac{2}{5} (x + 5)^{\frac{5}{2}} - \frac{10}{3} (x + 5)^{\frac{3}{2}} + C

Solution steps

\int x x + 5 d x

Apply u-substitution

: \int (u - 5) u d u

= \int (u - 5) u d u

Expand

(u - 5) u : u^{\frac{3}{2}} - 5 u

= \int u^{\frac{3}{2}} - 5 u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u^{\frac{3}{2}} d u - \int 5 u d u

\int u^{\frac{3}{2}} d u = \frac{2}{5} u^{\frac{5}{2}}

\int 5 u d u = \frac{10}{3} u^{\frac{3}{2}}

= \frac{2}{5} u^{\frac{5}{2}} - \frac{10}{3} u^{\frac{3}{2}}

Substitute back

u = x + 5

= \frac{2}{5} (x + 5)^{\frac{5}{2}} - \frac{10}{3} (x + 5)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{5} (x + 5)^{\frac{5}{2}} - \frac{10}{3} (x + 5)^{\frac{3}{2}} + C

\frac{x ^{2} - 4}{x}

8 sin (x)

x y^{^{'}} + 2 y = 4 e^{x}

\int_{- 1}^{0} (x - 2) d x

x \to - \infty lim (\frac{x + 3 e ^{2 x}}{x + e ^{2 x}})

What is the integral of (xsqrt(x+5)) ?
The integral of (xsqrt(x+5)) is 2/5 (x+5)^{5/2}-10/3 (x+5)^{3/2}+C