en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of g(x)=x^3-7x^2+2x+40

Solution

derivative of

g (x) = x^{3} - 7 x^{2} + 2 x + 40

Solution

3 x^{2} - 14 x + 2

Solution steps

\frac{d}{d x} (x^{3} - 7 x^{2} + 2 x + 40)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (7 x^{2}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (40)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (7 x^{2}) = 14 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (40) = 0

= 3 x^{2} - 14 x + 2 + 0

Simplify

= 3 x^{2} - 14 x + 2

Popular Examples

derivative of 2e^{-4x}

\frac{d}{d x} (2 e^{- 4 x})

integral of 1/((9x^2+1)^{5/2)}

\int \frac{1}{( 9 x ^{2} + 1 ) ^{\frac{5}{2}}} d x

volumeabout x=-1,x=y^3,[0,1]volume about

x = - 1, x = y^{3}, [0, 1]

derivative of sqrt(8+cot^2(x))

\frac{d}{d x} (8 + cot^{2} (x))

limit as x approaches 2 of 3x^3+x^2-8

x \to 2 lim (3 x^{3} + x^{2} - 8)

Frequently Asked Questions (FAQ)

What is the derivative of g(x)=x^3-7x^2+2x+40 ?
The derivative of g(x)=x^3-7x^2+2x+40 is 3x^2-14x+2
What is the first derivative of g(x)=x^3-7x^2+2x+40 ?
The first derivative of g(x)=x^3-7x^2+2x+40 is 3x^2-14x+2