What is the sum from n=1 to infinity of 1/(n^{0.5)} ?

The sum from n=1 to infinity of 1/(n^{0.5)} is diverges

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sum from n=1 to infinity of 1/(n^{0.5)}

n = 1 \sum \infty \frac{1}{n ^{0.5}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{0.5}}

Apply p-Series Test:

diverges

= diverges

\frac{d}{d t} (4 e^{- 3 t})

\frac{d}{d A} (- cos (2) (A) - sin (2) (A))

\int \frac{1}{x + y} d x

f (x) = \frac{2 x ^{2} + 4 x + 2}{x}

\frac{\partial}{\partial x} (y + 3 x y^{2} - 18)

What is the sum from n=1 to infinity of 1/(n^{0.5)} ?
The sum from n=1 to infinity of 1/(n^{0.5)} is diverges