What is the derivative of y=(x^2+2x)^2 ?

The derivative of y=(x^2+2x)^2 is 2(x^2+2x)(2x+2)

What is the first derivative of y=(x^2+2x)^2 ?

The first derivative of y=(x^2+2x)^2 is 2(x^2+2x)(2x+2)

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derivative of

y = (x^{2} + 2 x)^{2}

2 (x^{2} + 2 x) (2 x + 2)

Solution steps

\frac{d}{d x} ((x^{2} + 2 x)^{2})

Apply the chain rule:

2 (x^{2} + 2 x) \frac{d}{d x} (x^{2} + 2 x)

= 2 (x^{2} + 2 x) \frac{d}{d x} (x^{2} + 2 x)

\frac{d}{d x} (x^{2} + 2 x) = 2 x + 2

= 2 (x^{2} + 2 x) (2 x + 2)

\frac{d}{d x} (\frac{1}{2 \cdot ln ( x ^{2} + y ^{2} )})

\frac{d}{d x} (x + 2 y + 3 z)

y^{3} (x^{2} + 2)

y = 5^{9 x - 5}

1 + cos (x)

What is the derivative of y=(x^2+2x)^2 ?
The derivative of y=(x^2+2x)^2 is 2(x^2+2x)(2x+2)
What is the first derivative of y=(x^2+2x)^2 ?
The first derivative of y=(x^2+2x)^2 is 2(x^2+2x)(2x+2)