What is the derivative of 3t^5+3t^3-5 ?

The derivative of 3t^5+3t^3-5 is 15t^4+9t^2

What is the first derivative of 3t^5+3t^3-5 ?

The first derivative of 3t^5+3t^3-5 is 15t^4+9t^2

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derivative of

3 t^{5} + 3 t^{3} - 5

15 t^{4} + 9 t^{2}

Solution steps

\frac{d}{d t} (3 t^{5} + 3 t^{3} - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (3 t^{5}) + \frac{d}{d t} (3 t^{3}) - \frac{d}{d t} (5)

\frac{d}{d t} (3 t^{5}) = 15 t^{4}

\frac{d}{d t} (3 t^{3}) = 9 t^{2}

\frac{d}{d t} (5) = 0

= 15 t^{4} + 9 t^{2} - 0

Simplify

= 15 t^{4} + 9 t^{2}

(2 x + 3)^{3}

y = 3 x (\frac{x}{2 + 2})

1 + sin (x)

sin (x) + 2 x cos (x)

y = x^{2} + 7

What is the derivative of 3t^5+3t^3-5 ?
The derivative of 3t^5+3t^3-5 is 15t^4+9t^2
What is the first derivative of 3t^5+3t^3-5 ?
The first derivative of 3t^5+3t^3-5 is 15t^4+9t^2