What is the derivative of 1+sin(x) ?

The derivative of 1+sin(x) is cos(x)

What is the first derivative of 1+sin(x) ?

The first derivative of 1+sin(x) is cos(x)

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derivative of

1 + sin (x)

cos (x)

Solution steps

\frac{d}{d x} (1 + sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (sin (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (sin (x)) = cos (x)

= 0 + cos (x)

Simplify

= cos (x)

sin (x) + 2 x cos (x)

y = x^{2} + 7

2 sin (2 + 3 x^{2})

5 x^{7} + 6 x^{4} - 2

\frac{y ^{2}}{2}

What is the derivative of 1+sin(x) ?
The derivative of 1+sin(x) is cos(x)
What is the first derivative of 1+sin(x) ?
The first derivative of 1+sin(x) is cos(x)