What is the derivative of 1/(2^x) ?

The derivative of 1/(2^x) is -ln(2)*2^{-x}

What is the first derivative of 1/(2^x) ?

The first derivative of 1/(2^x) is -ln(2)*2^{-x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{1}{2 ^{x}}

- ln (2) \cdot 2^{- x}

Solution steps

\frac{d}{d x} (\frac{1}{2 ^{x}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} (2^{- x})

Apply exponent rule:

a^{b} = e^{b l n (a)}

2^{- x} = e^{(- x) l n (2)}

= \frac{d}{d x} (e^{(- x) l n (2)})

Apply the chain rule:

e^{(- x) l n (2)} \frac{d}{d x} ((- x) ln (2))

= e^{(- x) l n (2)} \frac{d}{d x} ((- x) ln (2))

\frac{d}{d x} ((- x) ln (2)) = - ln (2)

= e^{(- x) l n (2)} (- ln (2))

Simplify

e^{(- x) l n (2)} (- ln (2)) : - ln (2) \cdot 2^{- x}

= - ln (2) \cdot 2^{- x}

(1 + 2 x)^{x}

\frac{( x ^{2} - x + 1 )}{( a ^{3} - 3 )}

\frac{d}{d t} (a^{2} t)

(3^{x})^{2}

\frac{d}{d s} (3 s)

What is the derivative of 1/(2^x) ?
The derivative of 1/(2^x) is -ln(2)*2^{-x}
What is the first derivative of 1/(2^x) ?
The first derivative of 1/(2^x) is -ln(2)*2^{-x}