What is the derivative of (e^x)/2+(e^{-x})/2 ?

The derivative of (e^x)/2+(e^{-x})/2 is 1/2 e^x-1/2 e^{-x}

What is the first derivative of (e^x)/2+(e^{-x})/2 ?

The first derivative of (e^x)/2+(e^{-x})/2 is 1/2 e^x-1/2 e^{-x}

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derivative of

\frac{e ^{x}}{2} + \frac{e ^{- x}}{2}

\frac{1}{2} e^{x} - \frac{1}{2} e^{- x}

Solution steps

\frac{d}{d x} (\frac{e ^{x}}{2} + \frac{e ^{- x}}{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{e ^{x}}{2}) + \frac{d}{d x} (\frac{e ^{- x}}{2})

\frac{d}{d x} (\frac{e ^{x}}{2}) = \frac{1}{2} e^{x}

\frac{d}{d x} (\frac{e ^{- x}}{2}) = - \frac{1}{2} e^{- x}

= \frac{1}{2} e^{x} - \frac{1}{2} e^{- x}

\frac{( x ^{3} - x ^{2} + 2 )}{( x ^{2} - 4 )}

2 x^{2} + 9

2 x^{2} + 2

sin^{- 2} (x)

\frac{( x + 1 )}{2}

What is the derivative of (e^x)/2+(e^{-x})/2 ?
The derivative of (e^x)/2+(e^{-x})/2 is 1/2 e^x-1/2 e^{-x}
What is the first derivative of (e^x)/2+(e^{-x})/2 ?
The first derivative of (e^x)/2+(e^{-x})/2 is 1/2 e^x-1/2 e^{-x}