What is the derivative of 5^sinx ?

The derivative of 5^sinx is inx*5^sln(5)

What is the first derivative of 5^sinx ?

The first derivative of 5^sinx is inx*5^sln(5)

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derivative of

5^{s} in x

in x \cdot 5^{s} ln (5)

Solution steps

\frac{d}{d s} (5^{s} in x)

Treat

i, n, x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= in x \frac{d}{d s} (5^{s})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= in x \cdot 5^{s} ln (5)

(x + 1)^{3} (5 - x)

2 x^{4} - x^{2}

\frac{1}{tan ^{2} ( x )}

e (x^{2})

\frac{d}{d p} (210 + 16 p)

What is the derivative of 5^sinx ?
The derivative of 5^sinx is inx*5^sln(5)
What is the first derivative of 5^sinx ?
The first derivative of 5^sinx is inx*5^sln(5)