What is the derivative of (8x^2)/3 ?

The derivative of (8x^2)/3 is (16x)/3

What is the first derivative of (8x^2)/3 ?

The first derivative of (8x^2)/3 is (16x)/3

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derivative of

\frac{8 x ^{2}}{3}

\frac{16 x}{3}

Solution steps

\frac{d}{d x} (\frac{8 x ^{2}}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{8}{3} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{8}{3} \cdot 2 x^{2 - 1}

Simplify

\frac{8}{3} \cdot 2 x^{2 - 1} : \frac{16 x}{3}

= \frac{16 x}{3}

(1 - tan^{2} (x)) 3 (1 - sec^{2} (x)) 4

\frac{d}{d x} (\frac{1}{2 ln ( x ^{2} + y ^{2} )})

x^{3} - 2 x^{2} - 3

y = cos (lo g_{4} (x))

\frac{( 3 x - 1 )}{( 2 x + 1 )}

What is the derivative of (8x^2)/3 ?
The derivative of (8x^2)/3 is (16x)/3
What is the first derivative of (8x^2)/3 ?
The first derivative of (8x^2)/3 is (16x)/3