What is the derivative of x^3-2x^2-3 ?

The derivative of x^3-2x^2-3 is 3x^2-4x

What is the first derivative of x^3-2x^2-3 ?

The first derivative of x^3-2x^2-3 is 3x^2-4x

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derivative of

x^{3} - 2 x^{2} - 3

3 x^{2} - 4 x

Solution steps

\frac{d}{d x} (x^{3} - 2 x^{2} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3) = 0

= 3 x^{2} - 4 x - 0

Simplify

= 3 x^{2} - 4 x

y = cos (lo g_{4} (x))

\frac{( 3 x - 1 )}{( 2 x + 1 )}

w \cdot r t x cos (3 x^{2} + 5)

2 i + 4 j

y = (x + 1)^{2} (x^{2} - 1)

What is the derivative of x^3-2x^2-3 ?
The derivative of x^3-2x^2-3 is 3x^2-4x
What is the first derivative of x^3-2x^2-3 ?
The first derivative of x^3-2x^2-3 is 3x^2-4x