What is the derivative of ((3x-1))/((2x+1)) ?

The derivative of ((3x-1))/((2x+1)) is 5/((2x+1)^2)

What is the first derivative of ((3x-1))/((2x+1)) ?

The first derivative of ((3x-1))/((2x+1)) is 5/((2x+1)^2)

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derivative of

\frac{( 3 x - 1 )}{( 2 x + 1 )}

\frac{5}{( 2 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 x - 1}{2 x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 3 x - 1 ) ( 2 x + 1 ) - \frac{d}{d x} ( 2 x + 1 ) ( 3 x - 1 )}{( 2 x + 1 ) ^{2}}

\frac{d}{d x} (3 x - 1) = 3

\frac{d}{d x} (2 x + 1) = 2

= \frac{3 ( 2 x + 1 ) - 2 ( 3 x - 1 )}{( 2 x + 1 ) ^{2}}

Expand

3 (2 x + 1) - 2 (3 x - 1) : 5

= \frac{5}{( 2 x + 1 ) ^{2}}

w \cdot r t x cos (3 x^{2} + 5)

2 i + 4 j

y = (x + 1)^{2} (x^{2} - 1)

ln (1 + x^{4})

\frac{d}{d x} ((lo g_{10} (6) \cdot x^{2})^{3})

What is the derivative of ((3x-1))/((2x+1)) ?
The derivative of ((3x-1))/((2x+1)) is 5/((2x+1)^2)
What is the first derivative of ((3x-1))/((2x+1)) ?
The first derivative of ((3x-1))/((2x+1)) is 5/((2x+1)^2)