What is the derivative of w*rtxcos(3x^2+5) ?

The derivative of w*rtxcos(3x^2+5) is wtxcos(3x^2+5)

What is the first derivative of w*rtxcos(3x^2+5) ?

The first derivative of w*rtxcos(3x^2+5) is wtxcos(3x^2+5)

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derivative of

w \cdot r t x cos (3 x^{2} + 5)

wt x cos (3 x^{2} + 5)

Solution steps

\frac{d}{d r} (w r t x cos (3 x^{2} + 5))

Treat

w, t, x

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= wt x cos (3 x^{2} + 5) \frac{d r}{d r}

Apply the common derivative:

\frac{d r}{d r} = 1

= wt x cos (3 x^{2} + 5) \cdot 1

Simplify

= wt x cos (3 x^{2} + 5)

2 i + 4 j

y = (x + 1)^{2} (x^{2} - 1)

ln (1 + x^{4})

\frac{d}{d x} ((lo g_{10} (6) \cdot x^{2})^{3})

(3 x^{2} - 5 x)^{45}

What is the derivative of w*rtxcos(3x^2+5) ?
The derivative of w*rtxcos(3x^2+5) is wtxcos(3x^2+5)
What is the first derivative of w*rtxcos(3x^2+5) ?
The first derivative of w*rtxcos(3x^2+5) is wtxcos(3x^2+5)