What is the derivative of 20q-2q^2 ?

The derivative of 20q-2q^2 is 20-4q

What is the first derivative of 20q-2q^2 ?

The first derivative of 20q-2q^2 is 20-4q

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derivative of

20 q - 2 q^{2}

20 - 4 q

Solution steps

\frac{d}{d q} (20 q - 2 q^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d q} (20 q) - \frac{d}{d q} (2 q^{2})

\frac{d}{d q} (20 q) = 20

\frac{d}{d q} (2 q^{2}) = 4 q

= 20 - 4 q

2 (3 t + 1)^{\frac{1}{2}}

\frac{d}{d t} (0.3 cos (30 t))

csc^{3} (x)

2 x^{2} - x + 1

y = 2 x^{2} + 3 x \cdot tan (x)

What is the derivative of 20q-2q^2 ?
The derivative of 20q-2q^2 is 20-4q
What is the first derivative of 20q-2q^2 ?
The first derivative of 20q-2q^2 is 20-4q