What is the derivative of y=2x+cos(x) ?

The derivative of y=2x+cos(x) is 2-sin(x)

What is the first derivative of y=2x+cos(x) ?

The first derivative of y=2x+cos(x) is 2-sin(x)

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derivative of

y = 2 x + cos (x)

2 - sin (x)

Solution steps

\frac{d}{d x} (2 x + cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (cos (x))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (cos (x)) = - sin (x)

= 2 - sin (x)

y = x (3 - 4 x)

x^{2} - y^{2}

\frac{1}{( x + 2 ) ^{2}}

\frac{( x - m ^{2} )}{( x + 1 )}

\frac{d}{d t} (5 - 6 t + t^{2})

What is the derivative of y=2x+cos(x) ?
The derivative of y=2x+cos(x) is 2-sin(x)
What is the first derivative of y=2x+cos(x) ?
The first derivative of y=2x+cos(x) is 2-sin(x)