What is the derivative of 1+cot(x) ?

The derivative of 1+cot(x) is -csc^2(x)

What is the first derivative of 1+cot(x) ?

The first derivative of 1+cot(x) is -csc^2(x)

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derivative of

1 + cot (x)

- csc^{2} (x)

Solution steps

\frac{d}{d x} (1 + cot (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (cot (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (cot (x)) = - csc^{2} (x)

= 0 - csc^{2} (x)

Simplify

= - csc^{2} (x)

sin (\frac{1}{z})

(1 + x)^{3} (1 - x)^{7}

ln (e^{l n (x^{3} + 1)})

y = (6 x - 3) (3 x + 9)

\frac{d}{d t} (100 + 10 t + 1.25 t)

What is the derivative of 1+cot(x) ?
The derivative of 1+cot(x) is -csc^2(x)
What is the first derivative of 1+cot(x) ?
The first derivative of 1+cot(x) is -csc^2(x)