What is the first derivative of t^2+2 ?

The first derivative of t^2+2 is 2t

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derivative of t^2+2

derivative of

t^{2} + 2

2 t

Solution steps

\frac{d}{d t} (t^{2} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{2}) + \frac{d}{d t} (2)

\frac{d}{d t} (t^{2}) = 2 t

\frac{d}{d t} (2) = 0

= 2 t + 0

Simplify

= 2 t

x^{3} - 3^{x}

f (x) = - x + 2

y = \frac{x ^{2} - x + 1}{a ^{3} - 3}

y = t^{2}

\frac{sec ( x )}{x ^{2}}