What is the derivative of 1/p ?

The derivative of 1/p is -1/(p^2)

What is the first derivative of 1/p ?

The first derivative of 1/p is -1/(p^2)

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derivative of

\frac{1}{p}

- \frac{1}{p ^{2}}

Solution steps

\frac{d}{d p} (\frac{1}{p})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d p} (p^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 1 \cdot p^{- 1 - 1}

Simplify

- 1 \cdot p^{- 1 - 1} : - \frac{1}{p ^{2}}

= - \frac{1}{p ^{2}}

\frac{1}{( 2 x - 1 )}

x^{2} y + 1

ln (x) ln (2 x)

\frac{d}{d x} (\frac{4}{2 x ^{2} - ( + 4 ) ( - 3 ) - ( - 6 ) ( - 2 )})

\frac{1}{n ( 1 + ln ( x ) ) ^{2}}