What is the derivative of 1/((2x-1)) ?

The derivative of 1/((2x-1)) is -2/((2x-1)^2)

What is the first derivative of 1/((2x-1)) ?

The first derivative of 1/((2x-1)) is -2/((2x-1)^2)

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derivative of

\frac{1}{( 2 x - 1 )}

- \frac{2}{( 2 x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x - 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((2 x - 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x - 1 ) ^{2}} \frac{d}{d x} (2 x - 1)

= - \frac{1}{( 2 x - 1 ) ^{2}} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= - \frac{1}{( 2 x - 1 ) ^{2}} \cdot 2

Simplify

- \frac{1}{( 2 x - 1 ) ^{2}} \cdot 2 : - \frac{2}{( 2 x - 1 ) ^{2}}

= - \frac{2}{( 2 x - 1 ) ^{2}}

x^{2} y + 1

ln (x) ln (2 x)

\frac{d}{d x} (\frac{4}{2 x ^{2} - ( + 4 ) ( - 3 ) - ( - 6 ) ( - 2 )})

\frac{1}{n ( 1 + ln ( x ) ) ^{2}}

\frac{d}{d y} (\frac{y}{2 x + 1})

What is the derivative of 1/((2x-1)) ?
The derivative of 1/((2x-1)) is -2/((2x-1)^2)
What is the first derivative of 1/((2x-1)) ?
The first derivative of 1/((2x-1)) is -2/((2x-1)^2)