What is the derivative of x_{6}x^2+9 ?

The derivative of x_{6}x^2+9 is 2x_{6}x

What is the first derivative of x_{6}x^2+9 ?

The first derivative of x_{6}x^2+9 is 2x_{6}x

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\frac{d}{d x} (x_{6} x^{2} + 9)

2 x_{6} x

Solution steps

\frac{d}{d x} (x_{6} x^{2} + 9)

Treat

x_{6}

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x_{6} x^{2}) + \frac{d}{d x} (9)

\frac{d}{d x} (x_{6} x^{2}) = 2 x_{6} x

\frac{d}{d x} (9) = 0

= 2 x_{6} x + 0

Simplify

= 2 x_{6} x

x = 5 t^{2} - 2 t + 7

\frac{d}{d a} (1 - 8 sin^{2} (a) cos^{2} (a))

(\frac{1}{5})^{x}

\frac{( x + 1 ) ( x - 2 )}{x ^{2}}

(- 1 + 2 t)^{- 1}

What is the derivative of x_{6}x^2+9 ?
The derivative of x_{6}x^2+9 is 2x_{6}x
What is the first derivative of x_{6}x^2+9 ?
The first derivative of x_{6}x^2+9 is 2x_{6}x