What is the derivative of x=5t^2-2t+7 ?

The derivative of x=5t^2-2t+7 is 10t-2

What is the first derivative of x=5t^2-2t+7 ?

The first derivative of x=5t^2-2t+7 is 10t-2

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derivative of

x = 5 t^{2} - 2 t + 7

10 t - 2

Solution steps

\frac{d}{d t} (5 t^{2} - 2 t + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (5 t^{2}) - \frac{d}{d t} (2 t) + \frac{d}{d t} (7)

\frac{d}{d t} (5 t^{2}) = 10 t

\frac{d}{d t} (2 t) = 2

\frac{d}{d t} (7) = 0

= 10 t - 2 + 0

Simplify

= 10 t - 2

\frac{d}{d a} (1 - 8 sin^{2} (a) cos^{2} (a))

(\frac{1}{5})^{x}

\frac{( x + 1 ) ( x - 2 )}{x ^{2}}

(- 1 + 2 t)^{- 1}

y = x^{3} + 2 x - 1

What is the derivative of x=5t^2-2t+7 ?
The derivative of x=5t^2-2t+7 is 10t-2
What is the first derivative of x=5t^2-2t+7 ?
The first derivative of x=5t^2-2t+7 is 10t-2