What is the derivative of-2ln(x) ?

The derivative of-2ln(x) is -2/x

What is the first derivative of-2ln(x) ?

The first derivative of-2ln(x) is -2/x

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derivative of

- 2 ln (x)

- \frac{2}{x}

Solution steps

\frac{d}{d x} (- 2 ln (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (ln (x))

Apply the common derivative:

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= - 2 \cdot \frac{1}{x}

Simplify

- 2 \cdot \frac{1}{x} : - \frac{2}{x}

= - \frac{2}{x}

f (x) = (x + sin (x))^{2}

\frac{d}{d x} (ln ((x - b)^{2}) - ln ((y - a)^{2}))

f (x) = x^{2} - 4 x + 9

e^{x} - y^{2}

\frac{d}{d t} (10 + 5 t)