What is the derivative of y=((x+1))/((x-1)) ?

The derivative of y=((x+1))/((x-1)) is -2/((x-1)^2)

What is the first derivative of y=((x+1))/((x-1)) ?

The first derivative of y=((x+1))/((x-1)) is -2/((x-1)^2)

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derivative of

y = \frac{( x + 1 )}{( x - 1 )}

- \frac{2}{( x - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x + 1}{x - 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x + 1 ) ( x - 1 ) - \frac{d}{d x} ( x - 1 ) ( x + 1 )}{( x - 1 ) ^{2}}

\frac{d}{d x} (x + 1) = 1

\frac{d}{d x} (x - 1) = 1

= \frac{1 \cdot ( x - 1 ) - 1 \cdot ( x + 1 )}{( x - 1 ) ^{2}}

Simplify

\frac{1 \cdot ( x - 1 ) - 1 \cdot ( x + 1 )}{( x - 1 ) ^{2}} : - \frac{2}{( x - 1 ) ^{2}}

= - \frac{2}{( x - 1 ) ^{2}}

\frac{d}{d x} ((10 x - 7 y) i - (7 x - 2 y) j)

y = 7 x^{3} + 2 x^{2} + 4 x

\frac{3 y ^{2}}{2}

f (x) = (3 x - 4)^{2} (x - 2)

(x^{2} + 2)^{- 1}

What is the derivative of y=((x+1))/((x-1)) ?
The derivative of y=((x+1))/((x-1)) is -2/((x-1)^2)
What is the first derivative of y=((x+1))/((x-1)) ?
The first derivative of y=((x+1))/((x-1)) is -2/((x-1)^2)