What is the derivative of (3y^2)/2 ?

The derivative of (3y^2)/2 is 3y

What is the first derivative of (3y^2)/2 ?

The first derivative of (3y^2)/2 is 3y

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derivative of

\frac{3 y ^{2}}{2}

3 y

Solution steps

\frac{d}{d y} (\frac{3 y ^{2}}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{3}{2} \frac{d}{d y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{3}{2} \cdot 2 y^{2 - 1}

Simplify

\frac{3}{2} \cdot 2 y^{2 - 1} : 3 y

= 3 y

f (x) = (3 x - 4)^{2} (x - 2)

(x^{2} + 2)^{- 1}

\frac{1}{( 1 + e ^{u} )}

ln ((1 + 3 x)^{2})

3 t + 4

What is the derivative of (3y^2)/2 ?
The derivative of (3y^2)/2 is 3y
What is the first derivative of (3y^2)/2 ?
The first derivative of (3y^2)/2 is 3y