What is the first derivative of y=8x-5 ?

The first derivative of y=8x-5 is 8

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derivative of y=8x-5

derivative of

y = 8 x - 5

8

Solution steps

\frac{d}{d x} (8 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) - \frac{d}{d x} (5)

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (5) = 0

= 8 - 0

Simplify

= 8

5 x^{4} + 8

ln^{2} (x^{3}) - 3

(x^{2} + 2 x)^{\frac{1}{2}}

2 x^{2} + x + 5

x^{2} lo g_{10} (\frac{1}{x})