What is the d/(dt)(100-10t+6t^2) ?

The d/(dt)(100-10t+6t^2) is 12t-10

What is the first d/(dt)(100-10t+6t^2) ?

The first d/(dt)(100-10t+6t^2) is 12t-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (100 - 10 t + 6 t^{2})

12 t - 10

Solution steps

\frac{d}{d t} (100 - 10 t + 6 t^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (100) - \frac{d}{d t} (10 t) + \frac{d}{d t} (6 t^{2})

\frac{d}{d t} (100) = 0

\frac{d}{d t} (10 t) = 10

\frac{d}{d t} (6 t^{2}) = 12 t

= 0 - 10 + 12 t

Simplify

= 12 t - 10

y = x^{7} + 3 x^{5} + 1

4 x^{\frac{1}{3}}

2 sin^{2} (t) + 8 cos^{2} (t)

\frac{( x + 2 ) ^{2}}{3}

(5 x + 2)^{7}

What is the d/(dt)(100-10t+6t^2) ?
The d/(dt)(100-10t+6t^2) is 12t-10
What is the first d/(dt)(100-10t+6t^2) ?
The first d/(dt)(100-10t+6t^2) is 12t-10