What is the derivative of 2sin^2(t)+8cos^2(t) ?

The derivative of 2sin^2(t)+8cos^2(t) is -6sin(2t)

What is the first derivative of 2sin^2(t)+8cos^2(t) ?

The first derivative of 2sin^2(t)+8cos^2(t) is -6sin(2t)

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derivative of

2 sin^{2} (t) + 8 cos^{2} (t)

- 6 sin (2 t)

Solution steps

\frac{d}{d t} (2 sin^{2} (t) + 8 cos^{2} (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 sin^{2} (t)) + \frac{d}{d t} (8 cos^{2} (t))

\frac{d}{d t} (2 sin^{2} (t)) = 2 sin (2 t)

\frac{d}{d t} (8 cos^{2} (t)) = - 8 sin (2 t)

= 2 sin (2 t) - 8 sin (2 t)

Simplify

= - 6 sin (2 t)

\frac{( x + 2 ) ^{2}}{3}

(5 x + 2)^{7}

\frac{d}{d t} (t^{3} + 7 t^{2} + 24 t + 12)

2 f (x) + x^{2}

y = 3 x^{10}

What is the derivative of 2sin^2(t)+8cos^2(t) ?
The derivative of 2sin^2(t)+8cos^2(t) is -6sin(2t)
What is the first derivative of 2sin^2(t)+8cos^2(t) ?
The first derivative of 2sin^2(t)+8cos^2(t) is -6sin(2t)