What is the derivative of y=x^7+3x^5+1 ?

The derivative of y=x^7+3x^5+1 is 7x^6+15x^4

What is the first derivative of y=x^7+3x^5+1 ?

The first derivative of y=x^7+3x^5+1 is 7x^6+15x^4

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derivative of

y = x^{7} + 3 x^{5} + 1

7 x^{6} + 15 x^{4}

Solution steps

\frac{d}{d x} (x^{7} + 3 x^{5} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{7}) + \frac{d}{d x} (3 x^{5}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{7}) = 7 x^{6}

\frac{d}{d x} (3 x^{5}) = 15 x^{4}

\frac{d}{d x} (1) = 0

= 7 x^{6} + 15 x^{4} + 0

Simplify

= 7 x^{6} + 15 x^{4}

4 x^{\frac{1}{3}}

2 sin^{2} (t) + 8 cos^{2} (t)

\frac{( x + 2 ) ^{2}}{3}

(5 x + 2)^{7}

\frac{d}{d t} (t^{3} + 7 t^{2} + 24 t + 12)

What is the derivative of y=x^7+3x^5+1 ?
The derivative of y=x^7+3x^5+1 is 7x^6+15x^4
What is the first derivative of y=x^7+3x^5+1 ?
The first derivative of y=x^7+3x^5+1 is 7x^6+15x^4