What is the d/(dt)(t^3+7t^2+24t+12) ?

The d/(dt)(t^3+7t^2+24t+12) is 3t^2+14t+24

What is the first d/(dt)(t^3+7t^2+24t+12) ?

The first d/(dt)(t^3+7t^2+24t+12) is 3t^2+14t+24

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\frac{d}{d t} (t^{3} + 7 t^{2} + 24 t + 12)

3 t^{2} + 14 t + 24

Solution steps

\frac{d}{d t} (t^{3} + 7 t^{2} + 24 t + 12)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{3}) + \frac{d}{d t} (7 t^{2}) + \frac{d}{d t} (24 t) + \frac{d}{d t} (12)

\frac{d}{d t} (t^{3}) = 3 t^{2}

\frac{d}{d t} (7 t^{2}) = 14 t

\frac{d}{d t} (24 t) = 24

\frac{d}{d t} (12) = 0

= 3 t^{2} + 14 t + 24 + 0

Simplify

= 3 t^{2} + 14 t + 24

2 f (x) + x^{2}

y = 3 x^{10}

\frac{d}{d x} (a + b^{1} x^{1} + b^{2} x^{2} e)

sec^{2} (3 x^{2} - 7 x + 4)

y = (x + 2) (x^{2} + 1)

What is the d/(dt)(t^3+7t^2+24t+12) ?
The d/(dt)(t^3+7t^2+24t+12) is 3t^2+14t+24
What is the first d/(dt)(t^3+7t^2+24t+12) ?
The first d/(dt)(t^3+7t^2+24t+12) is 3t^2+14t+24