What is the derivative of 2f(x)+x^2 ?

The derivative of 2f(x)+x^2 is 2x

What is the first derivative of 2f(x)+x^2 ?

The first derivative of 2f(x)+x^2 is 2x

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derivative of

2 f (x) + x^{2}

2 x

Solution steps

\frac{d}{df} (2 f x + x^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{df} (2 f x) + \frac{d}{df} (x^{2})

\frac{d}{df} (2 f x) = 2 x

\frac{d}{df} (x^{2}) = 0

= 2 x + 0

Simplify

= 2 x

y = 3 x^{10}

\frac{d}{d x} (a + b^{1} x^{1} + b^{2} x^{2} e)

sec^{2} (3 x^{2} - 7 x + 4)

y = (x + 2) (x^{2} + 1)

h (x) = \frac{5}{6 x ^{5}}

What is the derivative of 2f(x)+x^2 ?
The derivative of 2f(x)+x^2 is 2x
What is the first derivative of 2f(x)+x^2 ?
The first derivative of 2f(x)+x^2 is 2x