What is derivative of x^2+y^2=2xy ?

The answer to derivative of x^2+y^2=2xy is (dy)/(dx)=1

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derivative of x^2+y^2=2xy

derivative of

x^{2} + y^{2} = 2 x y

\frac{d y}{d x} = 1

Solution steps

x^{2} + y^{2} = 2 x y

Treat

y

y (x)

Differentiate both sides:

2 x + 2 y \frac{d y}{d x} = 2 (y + x \frac{d y}{d x})

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = 1

\frac{d y}{d x} = 1

v = 2 - 4 t - 6 t^{3}

4 y = - 8 x + 2 x + 0

y^{2} = x

x^{2} + y^{2} = 6 x + 4 y

x = \frac{u - 1}{2}

What is derivative of x^2+y^2=2xy ?
The answer to derivative of x^2+y^2=2xy is (dy)/(dx)=1