What is derivative of x^2=2+t ?

The answer to derivative of x^2=2+t is (dx)/(dt)= 1/(2x)

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derivative of x^2=2+t

derivative of

x^{2} = 2 + t

\frac{d x}{d t} = \frac{1}{2 x}

Solution steps

x^{2} = 2 + t

Treat

x

x (t)

Differentiate both sides:

2 x \frac{d x}{d t} = 1

Isolate

\frac{d x}{d t} : \frac{d x}{d t} = \frac{1}{2 x}

\frac{d x}{d t} = \frac{1}{2 x}

y^{2} = 4 a (x + a)

x = \frac{( 1 + t ) ^{3}}{t ^{2}}

y^{2} = 2 x

x^{2} y^{2} = 1

x = (t^{2} + 1)^{\frac{1}{2}}

What is derivative of x^2=2+t ?
The answer to derivative of x^2=2+t is (dx)/(dt)= 1/(2x)