What is the solution for (d^3-3d+2)*y=x ?

The solution for (d^3-3d+2)*y=x is y=c_{1}e^{-2x}+c_{2}e^x+c_{3}xe^x+x/2+3/4

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(d^3-3d+2)*y=x

(d^{3} - 3 d + 2) \cdot y = x

y = c_{1} e^{- 2 x} + c_{2} e^{x} + c_{3} x e^{x} + \frac{x}{2} + \frac{3}{4}

Solution steps

(d^{3} - 3 d + 2) y = x

Solve linear ODE:

y = c_{1} e^{- 2 x} + c_{2} e^{x} + c_{3} x e^{x} + \frac{x}{2} + \frac{3}{4}

y = c_{1} e^{- 2 x} + c_{2} e^{x} + c_{3} x e^{x} + \frac{x}{2} + \frac{3}{4}

y^{^{'''}} - 4 y^{^{''}} = 2 x + 3

y^{^{''}} - 3 y^{^{'}} + 2 y = e^{3} t

(d^{2} - d - 2) y = 6 e^{\frac{- t}{2}}

d, d (q) = - 0.4 q + 23

(d^{2} + 4) y = 4 sin^{2} (x)

What is the solution for (d^3-3d+2)*y=x ?
The solution for (d^3-3d+2)*y=x is y=c_{1}e^{-2x}+c_{2}e^x+c_{3}xe^x+x/2+3/4