What is (\partial)/(\partial y)(cos(x^3y^3)) ?

The answer to (\partial)/(\partial y)(cos(x^3y^3)) is -sin(x^3y^3)*3x^3y^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(cos(x^3y^3))

\frac{\partial}{\partial y} (cos (x^{3} y^{3}))

- sin (x^{3} y^{3}) \cdot 3 x^{3} y^{2}

Solution steps

\frac{\partial}{\partial y} (cos (x^{3} y^{3}))

Treat

x

as a constant

Apply the chain rule:

- sin (x^{3} y^{3}) \frac{\partial}{\partial y} (x^{3} y^{3})

= - sin (x^{3} y^{3}) \frac{\partial}{\partial y} (x^{3} y^{3})

\frac{\partial}{\partial y} (x^{3} y^{3}) = 3 x^{3} y^{2}

= - sin (x^{3} y^{3}) \cdot 3 x^{3} y^{2}

\frac{\partial}{\partial x} (- 2 x y sin (x y^{2}))

tan^{2} (x)

y^{^{'}} = y - x^{2} + 1, y (0) = 0

\int \frac{b - x}{x} d x

\frac{\partial}{\partial x} (\frac{e ^{y}}{x + y ^{3}})

What is (\partial)/(\partial y)(cos(x^3y^3)) ?
The answer to (\partial)/(\partial y)(cos(x^3y^3)) is -sin(x^3y^3)*3x^3y^2