What is the slope of y=x-x^3,(1,0) ?

The slope of y=x-x^3,(1,0) is -2

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slope of y=x-x^3,(1,0)

slope

y = x - x^{3}, (1, 0)

- 2

Solution steps

y = x - x^{3}

In order to find the slope of the function, take the derivative of

x - x^{3}

\frac{d}{d x} (x - x^{3}) = 1 - 3 x^{2}

1 - 3 x^{2}

Find the value of

1 - 3 x^{2}

for

x = 1 : - 2

- 2

\frac{\partial}{\partial x} (- 2 x y z^{2} + 12)

2 x^{3} - x^{2} + 4

10 sin (6 t)

\int \frac{x}{x - x ^{2}} d x

k = 2 \sum \infty (\frac{1}{3})^{k}