en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of t^2+1

Solution

\int t^{2} + 1 d t

Solution

\frac{t ^{3}}{3} + t + C

Solution steps

\int t^{2} + 1 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int t^{2} d t + \int 1 d t

\int t^{2} d t = \frac{t ^{3}}{3}

\int 1 d t = t

= \frac{t ^{3}}{3} + t

Add a constant to the solution

= \frac{t ^{3}}{3} + t + C

Popular Examples

derivative of sqrt(x-2y)

\frac{d}{d x} (x - 2 y)

tangent of f(x)=x^2-2x-8,\at x=-2 tangent of

f (x) = x^{2} - 2 x - 8, at x = - 2

area y=((3x+1))/2 ,y=x^2-2 area

y = \frac{( 3 x + 1 )}{2}, y = x^{2} - 2

xy(dy)/(dx)+y^2=32x

x y \frac{d y}{d x} + y^{2} = 32 x

integral of x/(sqrt(4-x^2))

\int \frac{x}{4 - x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the integral of t^2+1 ?
The integral of t^2+1 is (t^3)/3+t+C