What is area y=((3x+1))/2 ,y=x^2-2 ?

The answer to area y=((3x+1))/2 ,y=x^2-2 is 343/48

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area y=((3x+1))/2 ,y=x^2-2

area

y = \frac{( 3 x + 1 )}{2}, y = x^{2} - 2

\frac{343}{48}

Decimal Notation

7.14583 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{\frac{5}{2}} \frac{1}{2} (3 x + 1) - (x^{2} - 2) d x

Solve

\int_{- 1}^{\frac{5}{2}} \frac{1}{2} (3 x + 1) - (x^{2} - 2) d x : \frac{343}{48}

The area is:

= \frac{343}{48}

x y \frac{d y}{d x} + y^{2} = 32 x

\int \frac{x}{4 - x ^{2}} d x

\int 2 x + 9 d x

2 t y^{^{'}} - 3 y = 0

f (x) = \frac{7}{x ^{4}}, at x = - 3

What is area y=((3x+1))/2 ,y=x^2-2 ?
The answer to area y=((3x+1))/2 ,y=x^2-2 is 343/48