What is the sum from n=0 to infinity of (2^nz^n)/n ?

The sum from n=0 to infinity of (2^nz^n)/n is Radius of convergence is 1/2

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sum from n=0 to infinity of (2^nz^n)/n

n = 0 \sum \infty \frac{2 ^{n} z ^{n}}{n}

Radius of convergence is \frac{1}{2}

Solution steps

n = 0 \sum \infty \frac{2 ^{n} z ^{n}}{n}

Use the Ratio Test to compute the convergence interval

Radius of convergence is \frac{1}{2}

\frac{d}{d x} (x^{4} e^{8 x})

\frac{d}{d x} (I n (x^{2} + 1))

\frac{\partial}{\partial z} (2 x z^{2})

x \to \infty lim (x^{a})

y = 2 x - 2 x^{2}, at x = - 1.5

What is the sum from n=0 to infinity of (2^nz^n)/n ?
The sum from n=0 to infinity of (2^nz^n)/n is Radius of convergence is 1/2