What is the integral from infinity to x of 1/(x^2) ?

The integral from infinity to x of 1/(x^2) is -1/x

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integral from infinity to x of 1/(x^2)

\int_{\infty}^{x} \frac{1}{x ^{2}} d x

- \frac{1}{x}

Solution steps

\int_{\infty}^{x} \frac{1}{x ^{2}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{2}} d x = - \frac{1}{x} + C

Compute the boundaries:

\int_{\infty}^{x} \frac{1}{x ^{2}} d x = - \frac{1}{x} - 0

= - \frac{1}{x} - 0

Simplify

= - \frac{1}{x}

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What is the integral from infinity to x of 1/(x^2) ?
The integral from infinity to x of 1/(x^2) is -1/x