What is the integral from x^2 to x^3 of sin(x) ?

The integral from x^2 to x^3 of sin(x) is -cos(x^3)+cos(x^2)

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integral from x^2 to x^3 of sin(x)

\int_{x^{2}}^{x^{3}} sin (x) d x

- cos (x^{3}) + cos (x^{2})

Solution steps

\int_{x^{2}}^{x^{3}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{x^{2}}^{x^{3}}

Compute the boundaries:

- cos (x^{3}) + cos (x^{2})

= - cos (x^{3}) + cos (x^{2})

\int_{0}^{l n (13)} tanh (x) d x

\int_{0}^{2} \frac{1}{y} d y

\int_{2}^{3} \frac{1}{2} d x

\int_{0}^{3 π} 1 + cos (x) d x

\int_{0}^{0.8} x e^{x} d x

What is the integral from x^2 to x^3 of sin(x) ?
The integral from x^2 to x^3 of sin(x) is -cos(x^3)+cos(x^2)