What is the derivative of 2+ln(x) ?

The derivative of 2+ln(x) is 1/x

What is the first derivative of 2+ln(x) ?

The first derivative of 2+ln(x) is 1/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2 + ln (x))

\frac{1}{x}

Solution steps

\frac{d}{d x} (2 + ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (ln (x))

\frac{d}{d x} (2) = 0

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 0 + \frac{1}{x}

Simplify

= \frac{1}{x}

y^{^{'}} + 4 x y = x

\frac{d}{d x} (ln (1 + x^{4}))

\int_{4}^{\infty} e^{- \frac{y}{2}} d y

\int \frac{1}{3 - x ^{2}} d x

\int (sin (5 x) sin (x)) d x

What is the derivative of 2+ln(x) ?
The derivative of 2+ln(x) is 1/x
What is the first derivative of 2+ln(x) ?
The first derivative of 2+ln(x) is 1/x