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Popular >

integral from-1 to 0 of (2y+2)

Solution

\int_{- 1}^{0} (2 y + 2) d y

Solution

1

Solution steps

\int_{- 1}^{0} 2 y + 2 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} 2 y d y + \int_{- 1}^{0} 2 d y

\int_{- 1}^{0} 2 y d y = - 1

\int_{- 1}^{0} 2 d y = 2

= - 1 + 2

Simplify

= 1

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 0 of (2y+2) ?
The integral from-1 to 0 of (2y+2) is 1